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PHP calculate age

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I'm looking for a way to calculate the age of a person, given their DOB in the format dd/mm/yyyy.

I was using the following function which worked fine for several months until some kind of glitch caused the while loop to never end and grind the entire site to a halt. Since there are almost 100,000 DOBs going through this function several times a day, it's hard to pin down what was causing this.

Does anyone have a more reliable way of calculating the age?

//replace / with - so strtotime works
$dob = strtotime(str_replace("/","-",$birthdayDate));       
$tdate = time();

$age = 0;
while( $tdate > $dob = strtotime('+1 year', $dob))
{
    ++$age;
}
return $age;

EDIT: this function seems to work OK some of the time, but returns "40" for a DOB of 14/09/1986

return floor((time() - strtotime($birthdayDate))/31556926);

 

  • PHP

  • asked 3 years ago
  • Gul Hafiz

5Answer


0

This works fine.


<?php
  //date in mm/dd/yyyy format; or it can be in other formats as well
  $birthDate = "12/17/1983";
  //explode the date to get month, day and year
  $birthDate = explode("/", $birthDate);
  //get age from date or birthdate
  $age = (date("md", date("U", mktime(0, 0, 0, $birthDate[0], $birthDate[1], $birthDate[2]))) > date("md")
    ? ((date("Y") - $birthDate[2]) - 1)
    : (date("Y") - $birthDate[2]));
  echo "Age is:" . $age;
?>

 

  • answered 3 years ago
  • G John

0
 $date = new DateTime($bithdayDate);
 $now = new DateTime();
 $interval = $now->diff($date);
 return $interval->y;

 

  • answered 3 years ago
  • Gul Hafiz

0
$tz  = new DateTimeZone('Europe/Brussels');
$age = DateTime::createFromFormat('d/m/Y', '12/02/1973', $tz)
     ->diff(new DateTime('now', $tz))
     ->y;

As of PHP 5.3.0 you can use the handy DateTime::createFromFormat to ensure that your date does not get mistaken for m/d/Y format and the DateInterval class (via DateTime::diff) to get the number of years between now and the target date.

  • answered 3 years ago
  • Gul Hafiz

0

Simple method for calculating Age from dob:

$_age = floor((time() - strtotime('1986-09-16')) / 31556926);

31556926 is the number of seconds in a year.

  • answered 3 years ago
  • G John

0

If you want to caculate the Age of using the dob, you can also use this function. It uses the DateTime object.


function calcutateAge($dob){

        $dob = date("Y-m-d",strtotime($dob));

        $dobObject = new DateTime($dob);
        $nowObject = new DateTime();

        $diff = $dobObject->diff($nowObject);

        return $diff->y;

}

 

  • answered 3 years ago
  • G John

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  • asked 3 years ago
  • viewed 926 times
  • active 3 years ago

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